Solve Geometry Coordinate Homework: |Z-1|+|Z+1|=7

AI Thread Summary
The equation |Z-1|+|Z+1|=7 describes a locus of points in the complex plane. It represents an ellipse with foci at the points -1 and +1 on the real axis. The initial calculations attempted to derive a circle, but the correct interpretation reveals it is indeed an ellipse. Squaring both sides of the equation was noted as a potential error in the algebra. Understanding the geometric properties of the ellipse is crucial for accurately illustrating it on the Argand Diagram.
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Homework Statement


Given that Z is a complex number with condition |Z-1|+|Z+1|=7

Illustrate Z on Argand Diagram and write out the equation of Locuz Z


I attempted to figured out the equation of locus Z,
|Z-1|+|Z+1|=7
|x+yi-1|+|x+yi+1|=7
\sqrt{}[(x-1)^2+y^2] + \sqrt{}[(x+1)^2 + y^2] = 7
\sqr{}x^2 + 1 - 2x + y^2 + x^2 + 1 + 2x + y^2 = 49
\sqr{}2x^2 + 2y^2 = 47

it's not necessary the correct answer though...
however, I can't figure how to illustrate the diagram! help!
 
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Assuming that your calculations are correct, that gives a circle of radius \sqrt{47/2}. However, I don't think it is... Check your algebra carefully -- squaring both sides doesn't mean get rid of square roots!

Another way to think about it is that the original equation says that the distance from a point on the locus to the points +1 and -1 add up to 7. This is the condition for an ellipse with its foci at -1 and 1! And an ellipse is only a circle if the foci coincide.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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