Prove: Area of Triangle Between Vector a & b & Red Line = 1/2 |a x b|

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The discussion focuses on proving that the area of a triangle formed by vectors a and b, along with a red line, is equal to 1/2 |a x b|. The area formula A = 1/2 bh is acknowledged, with vector b assumed as the base. Participants are trying to determine the height of the triangle, which is related to vector a and the angle theta. Clarification is needed on how to express the height in terms of these variables. The conversation emphasizes understanding the geometric relationship between the vectors to complete the proof.
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1. Show that the area of the triangle contained between vector a and vector b and the red line is 1/2 |a x b|

So far i have that bcosO would equal a ...and that 1/2bh should be the area... but I am stuck. can somebody help me prove?
 
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b\cos\theta=a is not correct. Assuming vector b forms the base of the triangle, A=1/2bh is the correct equation for the area. So what is the height of the triangle? (Hint: it involves only a and theta).
 
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