Finding Perpendicular Tangent Point on Parabola

AI Thread Summary
To find the point on the parabola y = 4x^2 + 2x - 5 where the tangent line is perpendicular to the line 3x + 2y = 7, first determine the slope of the given line, which is -3/2. The slope of the tangent line must be the negative reciprocal, resulting in a slope of 2/3. By calculating the derivative of the parabola, dy/dx = 8x + 2, set this equal to 2/3 to find the x-value, which is -1/6. Substitute this x-value back into the original parabola equation to find the corresponding y-coordinate. This approach effectively identifies the perpendicular tangent point on the parabola.
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Homework Statement


Find the point on the parabola y= 4x^2 + 2x - 5 where the tangent line is perpendicular to the line 3x + 2y = 7.


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The Attempt at a Solution


I don't know what to do since I was away the last 3 classes since I was away. Help me please.
 
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You want to find the slope of the line you're given and use the definition of a derivative as well as perpendicularity to solve for the x value you want.
 
Two perpendicular lines have slopes that are negative reciprocals of each other, eg: a line with a slope 2 is perpendicular to a line with a slope -1/2.

Find the slope of the line, find the negative reciprocal of that slope. The derivative of a function is the slope of that graph at any point on the graph, so find the derivative of the parabola and see at what value of x it will equal the negative reciprocal of the slope you found earlier.
 
TMM said:
You want to find the slope of the line you're given and use the definition of a derivative as well as perpendicularity to solve for the x value you want.

So I take the slope of this? 3x + 2y = 7

so...

2y = -3x + 7
y= -3/2x + 7/2

slope = -3/2 so if it is perpendicular the slope is 2/3 is that my right slope?

I now I have to do more but it that right so far?
 
Yes.
 
Correct.

dy/dx = 8x+2
You want the value of x when dy/dx is (2/3), as you said from above.
Solving for x gets (-1/6).
Plug this value into your original equation y=4x^2 etc.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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