What Is the Equation of a Line Inclined at 130 Degrees Through (0,2)?

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To find the equation of a line inclined at 130 degrees through the point (0,2), the slope must be calculated using the tangent of the angle, which is the tangent of 130 degrees. The standard form of the line's equation is y = mx + b, where m represents the slope and b is the y-intercept, which is 2 in this case. The slope derived from the angle will be negative, reflecting the line's downward inclination. Understanding the relationship between the slope and the angle is crucial for formulating the equation correctly. The discussion emphasizes the need to connect the slope with the line's equation format.
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Homework Statement



find the equation of the line with the inclination 130 degrees going through point (0,2)

Homework Equations


The Attempt at a Solution



baffled at how to start...

thanks!
 
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What do you know about the equation of a line?
 
Maybe drawing it 1st will give you an idea of what the equation should be.

A line of inlcination 180\cdot going through (0,2) would have the equation: y = 2
 
What is the slope of the line?
 
for the past two days, I couldn't enter this site...

thanks, for the equation, this is all the information given...I assume it will be in a "y=mx+b" format, but I am not sure. also the slope has to be a 130 degree angle with the horizontal axis (I believe the x axis)...

if it helps, the class is math analyst, which is the one before calculus...

thanks!
 
No, the "slope" of a line, in this sense, is NOT the angle it makes with the x-axis, it is the tangent of that angle. Now, how is that "slope" connected with y= mx+ b?
 

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