Physical meaning of minus in Faraday's law of induction

AI Thread Summary
The discussion focuses on the interpretation of the negative sign in Faraday's law of induction, which states that the induced electromotive force (emf) is equal to the negative rate of change of magnetic flux. The minus sign reflects Lenz's law, indicating that the induced current opposes changes in magnetic flux. The right-hand rule is suggested as a method to determine the direction of the induced emf based on the defined magnetic field direction. Understanding the physical meaning of positive and negative emf requires establishing a reference direction for the magnetic flux. Ultimately, the minus sign serves as a reminder to apply Lenz's law when analyzing induced emf.
yoran
Messages
116
Reaction score
0
Hi,

I'm having some troubles with Faraday's law of induction:
\mathcal{E} = - {{d\Phi_B} \over dt}

I don't understand the meaning of the minus. I do understand that, according to the law of Lenz, the induced current is directed such that it counters the change in magnetic flux. But I don't see how the induced emf can have a direction (positive or negative) because if the magnetic flux is increasing, the induced emf is negative and when the magnetic flux is decreasing, the induced emf is positive. But in a circuit where there is an induced emf, what is the physical meaning of a negative or positive emf?

Thank you.
 
Physics news on Phys.org
right hand rule

To interpret the minus sign, use the right hand rule. Here's an example. Imagine a circular loop in the x-y plan and centered at the origin. Let's say we define the flux to be positive when the B field is pointing in the +z direction. If Faraday's law tells you that the sign of the EMF is positive, the right hand rule* will tell you that the EMF is counterclockwise (as viewed from the +z axis looked down towards the origin); if negative, then clockwise.

*If the thumb of your right hand points parallel or anti-parallel to +z axis (depending upon the sign of the EMF given by Faraday's law), the curl of your fingers will give you the orientation of the EMF.

Make sense?
 
Faraday's law of induction itself is confusing to me. Consider that the force x distance energy of pushing a coil against magnetism; converts to magnetic energy in the coil.

Force x distance relationships are independent of rate of movement through the force. Consider that in a demonstration related to the Meissner effect, a magnet placed above a superconductor is levitated. I suspect the levitation height is independent of magnet velocity before levitation.
 
I just think of the minus sign as a reminder to apply Lenz's Law when dealing with an induced emf.
 
Thanks guys I understand it now. So basically you have to define a reference direction in order to give a meaning to the minus sign.
 
Yeah, that seems right.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top