What is the Pauli-Lubanski Pseudo-Vector and How Can its Invariance be Proven?

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Discussion Overview

The discussion revolves around the Pauli-Lubanski pseudo-vector and the derivation of its square, W2. Participants are seeking assistance in proving specific mathematical results related to this concept, referencing equations from a particular paper.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant requests help to prove the result of W2, specifically starting from the expression Wa=(1/2)EabcdMbcPd and ending with W2=-(1/2)MabMabP2+MacMbcPaPb.
  • Another participant suggests using the identity involving the Levi-Civita symbol and the antisymmetry property of M_{ab} to aid in the derivation.
  • A later reply expresses frustration at obtaining a result of zero for the Pauli-Lubanski pseudo-vector, questioning the validity of their approach and suggesting that this outcome, while invariant, may not be meaningful.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the derivation of the Pauli-Lubanski pseudo-vector or the implications of obtaining a zero result. Multiple viewpoints and approaches are presented without resolution.

Contextual Notes

There are unresolved mathematical steps and assumptions regarding the derivation process, particularly concerning the identities used and the implications of the results obtained.

udaraabey
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Hi

I’m wondering if anybody could help me to prove the result of W2 (square of the pauli-lubanski pseudo-vecor).
 
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udaraabey said:
Hi

I’m wondering if anybody could help me to prove the result of W2 (square of the pauli-lubanski pseudo-vecor).

See first equation on page 117 of http://www.arxiv.org/abs/physics/0504062

Eugene.
 


Thank you for your reply but in my case I need to start with

Wa=(1/2)EabcdMbcPd

And to end with

W2=-(1/2)MabMabP2+MacMbcPaPb

Could anybody tell me how to derive this
 


Could anybody tell me how to derive this

use the identity

<br /> \epsilon_{a}^{bcd}\epsilon^{a \bar{b} \bar{c} \bar{d}} = - \left| \begin{array}{ccc} \eta^{\bar{b}b} &amp; \eta^{\bar{c}b} &amp; \eta^{\bar{d}b} \\ \eta^{\bar{b}c} &amp; \eta^{\bar{c}c} &amp; \eta^{\bar{d}c} \\ \eta^{\bar{b}d} &amp; \eta^{\bar{c}d} &amp; \eta^{\bar{d}d} \end{array} \right|<br />

and

M_{ab} = - M_{ba}


regards


sam
 


samalkhaiat said:
use the identity

<br /> \epsilon_{a}^{bcd}\epsilon^{a \bar{b} \bar{c} \bar{d}} = - \left| \begin{array}{ccc} \eta^{\bar{b}b} &amp; \eta^{\bar{c}b} &amp; \eta^{\bar{d}b} \\ \eta^{\bar{b}c} &amp; \eta^{\bar{c}c} &amp; \eta^{\bar{d}c} \\ \eta^{\bar{b}d} &amp; \eta^{\bar{c}d} &amp; \eta^{\bar{d}d} \end{array} \right|<br />

and

M_{ab} = - M_{ba}


regards


sam

i tried to get an explicit form of this (Pauli-Lubanski pseudo vector) and i keep getting
zero. i.e W=(0,0,0,0)...which would still make it an invariant; albeit a boring one.
Looking at the form too, with M_ab=-M_ba it does seem that it should be zero.
Can someone tell me what i might be doing wrong. Thanks
 

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