What is the minimum angle for box to start slipping?

AI Thread Summary
The discussion focuses on determining the minimum angle at which a box of textbooks begins to slip on a loading ramp, given its mass and friction coefficients. The calculations involve using the static friction coefficient to find the angle θ, where the forces acting on the box, including gravitational and frictional forces, are balanced. The net force is zero just before slipping occurs, leading to the equation -mg + usmgcosθ = 0. Once the angle is established, the acceleration of the box and its speed after sliding a distance of 4.8 m can be calculated. Understanding the forces and their components is crucial for solving the problem accurately.
anubis01
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Homework Statement


A box of textbooks of mass 24.0 Kg rests on a loading ramp that makes an angle θ with the horizontal. The coefficient of kinetic friction is 0.25 and the coefficient of static friction is 0.36.

a)As the angle is increased, find the minimum angle at which the box starts to slip
b)At this angle, find the acceleration once the box has begun to move
c)At this angle, how fast will the box be moving after it has slid a distance 4.8 m along the loading ramp?

Homework Equations


f=un
n=mgcosθ

The Attempt at a Solution


a)fs=usn=ma=0
usmgcosθ=0
θ=cos-1(-umg)
θ=cos-1(-0.36*24*9.8)
θ=cos^-1(-84.67)
This is pretty much the only question I'm having trouble with, b and c I can figure out once I find θ. As always any help is much appreciated.
 
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What forces act on the box? Just before it starts to slip, what's the net force on the box?
 
the forces that act on the box are fg and fs and the net force will be zero just before it starts so.
-mg+usmgcosθ=0
θ=cos-1(mg/umg)
 
anubis01 said:
the forces that act on the box are fg and fs and the net force will be zero just before it starts so.
Good. (But don't forget the normal force.)
-mg+usmgcosθ=0
Weight acts vertically; friction acts parallel to the incline. To combine forces in an equation, take components parallel to the incline.
 
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