Tension Required for 1200-kg Car @ 0.60m/s2

Thread starter annala
Start date Oct 20, 2008
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Rope Tension

AI Thread Summary

To determine the tension required to accelerate a 1200-kg car at 0.60 m/s², Newton's second law (F = ma) is applied. The force needed for acceleration is calculated by multiplying the mass of the car by the acceleration, resulting in a force of 720 N. This force represents the tension that the rope must withstand. Friction is ignored in this scenario, simplifying the calculations. The discussion emphasizes the application of fundamental physics principles to solve the problem.

Oct 20, 2008

annala

Homework Statement

How much tension must a rope withstand if it is used to accelerate a 1200-kg car at 0.60m/s²? Ignore friction

Homework Equations

The Attempt at a Solution

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Oct 20, 2008

tiny-tim

Science Advisor

Homework Helper

Welcome to PF!

annala said:

How much tension must a rope withstand if it is used to accelerate a 1200-kg car at 0.60m/s²?

Hi annala! Welcome to PF!

Use good ol' Newton's second law … F = ma.

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