Multiplying/Dividing Rational Expressions(Playing with AlgebraII Fractions)

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The discussion revolves around simplifying the rational expression [(4x-4x^2)/(x^2+2x-3)] * [(x^2+x-6)/4x]. The user breaks down the expression by factoring and canceling common terms, ultimately arriving at the simplified form of (-1)(x-2). There is a humorous exchange about the user's mental math process and concerns about potential cheating in homework help. The final confirmation from another participant validates the user's workings as correct. The conversation highlights the importance of showing work in math discussions for clarity and verification.
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Homework Statement


[(4x-4x2)/x2+2x-3] * [(x2+x-6)/4x]


Homework Equations





The Attempt at a Solution


I'm so lazy, though, I do all this stuff mentally, so... Oby-kaby.
I individualized all groups into smaller units(I don't know how to say that in algebrish), by dividing by least common factor.

[4x(-1)(x-1)]/[(x-1)(x+3)] * [(x+3)(x-2)]/4x

then I multiply numerators, and denominators,

[4x(-1)(x-1)(x+3)(x-2)]/[(x-1)(x+3)(4x)]

then I use numbers of similair values to kill each other, resulting in...

(-1)(x-2)

THEN I got done doing some stuff, I got -x+2, don't know if right. Trembling in fear of overdominating, atomic family junky, math commander. Don't drink and use PC's. Then I was concured, which is insanely close to conquered, then somebody got worried of me posting problems, with them cheating, supplementing the ase of cheating, which goes back to me typing the work, then this paragraph, which doesn't open a continuim in explanations. But leaves the same question, and a new one. Did he spell continuim right? WHAT?!?
 
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I concur.

The Bob
 
Well, we can't tell you whether or not you are right if you don't show us what you did!
 
WHAT?!? Concured? I edited, mentor, hoorah!
 
Did I do it right?
 
Heller?
 
SETHOSCOTT said:
Did I do it right?
The workings out are right.

The Bob
 
Sweet, muchas gracias, the bob.:!)
 
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