How Does Electric Force Compare to Gravitational Force in a Simple Atom?

AI Thread Summary
In a simple atom consisting of one electron and one proton, the electric force between them is calculated to be 28.8N using the formula F=K(qq)/r². The discussion raises questions about the gravitational forces acting on both particles, suggesting they should be equal and calculated using G(mpme)/R². However, the gravitational force of both the electron and proton is significantly smaller than the electric force. Clarifications are made regarding the wording of the gravitational force inquiry, emphasizing the need for precision in calculations. Overall, the electric force vastly outweighs the gravitational forces in atomic interactions.
Dell
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a simple atom is comprised of one electron and one proton, with a distance of R=0.5*10-10m between them

1) what is the electric force between them

F=K(qq)/r2 = 28.8N
------------------------------

2)how much smaller than the electric force is:
a) the gravitational force of the electron
b) the gravitational force of the proton

are the 2 gravitational forces not the same? is the force not equal to G(mpme)/R2 for both of them?
 
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Dell said:
a simple atom is comprised of one electron and one proton, with a distance of R=0.5*10-10m between them

1) what is the electric force between them

F=K(qq)/r2 = 28.8N
Better double check your arithmetic. 28.8N is huge (for atomic particles).

2)how much smaller than the electric force is:
a) the gravitational force of the electron
b) the gravitational force of the proton
This is worded strangely. Perhaps they meant the gravitational force on the particles.

are the 2 gravitational forces not the same? is the force not equal to G(mpme)/R2 for both of them?
Right.
 
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