A group that is a collection of sets

  • Thread starter Thread starter halvizo1031
  • Start date Start date
  • Tags Tags
    Group Sets
halvizo1031
Messages
77
Reaction score
0

Homework Statement


Let S be a set of things and let P be the set of subsets of S. For A, B in P define

A*B = ((S-A) intersect B) union (A intersect (S-B)).

Need to show that (P,*) is commutative and the group identity.


Homework Equations





The Attempt at a Solution



only attempted to show through venn diagrams..looking for an alternative approach?
 
Physics news on Phys.org
unless I'm missing something commutative seems pretty obvious from the definition of the multiplication, just re-arrange to show A*B = B*A

then try the follwing multiplications: A with the empty set & A with its complement
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top