Magnetic field generated by current in semicircular loop at a point on axis

AI Thread Summary
To determine the magnetic field strength and direction at a point on the axis of a semi-circular current loop, the Biot-Savart Law is applied. The problem is simplified by recognizing that the magnetic field components from a full loop cancel out, but the semi-circular arc and the straight line base must be analyzed separately. Using cylindrical coordinates is recommended for easier calculations, with the parametric representation of points on the semi-circle provided. The discussion emphasizes the importance of defining the position vectors and unit vectors correctly for accurate calculations. Participants are encouraged to share their results for verification.
SOMEBODYCOOL
Messages
5
Reaction score
0

Homework Statement


Determine the magnetic field strength and direction at a point 'z' on the axis of the centre of a semi-circular current loop of radius R.

Homework Equations


Biot Savart Formula
d\vec{B}=\frac{\mu_{0}Id\vec{r}\times\hat{e}}{4\pi|\vec{R}-\vec{r}|^{2}}

e being the unit vector from r to R

The Attempt at a Solution


A much simpler problem is a full current loop, because one component of the magnetic field cancels out. For this problem, you'd have to deal with the half-circle arc and the straight line base separately. I was also wondering whether its easier to calculate the z and x components of B separately as well... One component is straightforward enough... I just really don't understand where to start.
 
Last edited:
Physics news on Phys.org
This should be a pretty straightforward application of the Biot-Savart Law. Start by finding expressions for \textbf{r}, the position vector for a general point on the semi-circular arc, and \textbf{R} the position vector for a general point on the z-axis...what do you get for those?...What does that make \hat{\mathbf{e}}? What is d\textbf{r} for a semi-circualr arc?

To makethings easier, you will want to use cylindrical coordinates.
 
So, the parametric representation of a point on the semi-circle would be (0, bcos(t), bsin(t)) where b is the radius of the semi-circle.
The vector R is just [d, 0, 0] where d is the distance on the axis of the point
and then the e is the unit vector from R-r
But what's dr? And where does the switch to cylindrical coord come in?
 
I think I got it. Thanks
 
SOMEBODYCOOL said:
I think I got it. Thanks

If you'd like to post your result, we''ll be able to check it for you.
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top