Defibrillator discharges. need to find time constant

AI Thread Summary
A defibrillator discharges a capacitor through a patient, with a capacitance of 60 microfarads and a resistance of 220 ohms, charged to 5 kilovolts for 1 millisecond. The time constant is calculated as R*C, resulting in a value of 1.32*10^-2 seconds, which is significantly larger than 1 millisecond. To find the charge remaining on the capacitor after 1 millisecond, the equation Q=C*V*e^(-t/RC) can be used. For the total charge delivered to the patient, the formula Q=C*V is appropriate, while the average current can be determined using V=IR. The discussion highlights the importance of correctly interpreting the time constant and applying the right equations for each part of the problem.
gujrichick
Messages
3
Reaction score
0
A defibrillator uses a capacitor to deliver a large current to a person needing heart stimulation. Assume that the capacitance used is 60microfarads and the resistor it discharges through is 220 ohms. the defibrillator is charged up to 5 kiloVolts and it is discharged through a patient for 1.0 millisecond.

a) What fraction of the time constant is 1.0 millisecond?
b) How much charge is left on the capacitor after the 1.0 millisecond?
c) Find the total charge delivered to the patient.
d) Determine the average current delivered to the patient.'

I used time constant=R*C to find the time constant but it comes out to be smaller than 1.0ms, which does not make sense. I just need to know which equations to use to get the answers right.

Please help. And Thanks to whoever helps!
 
Physics news on Phys.org
Welcome to PF!

gujrichick said:
A defibrillator uses a capacitor to deliver a large current to a person needing heart stimulation. Assume that the capacitance used is 60microfarads and the resistor it discharges through is 220 ohms. the defibrillator is charged up to 5 kiloVolts and it is discharged through a patient for 1.0 millisecond.

a) What fraction of the time constant is 1.0 millisecond?

I used time constant=R*C to find the time constant but it comes out to be smaller than 1.0ms …

Hi gujrichick! Welcome to PF! :smile:

What did you get for the time constant? :confused:
 
Hi,

I got 1.32*10^-5 seconds as my time constant.. and I don't understand how I would get a fraction from that or how that would help me answer the other questions.
 
Hi gujrichick! :smile:

(try using the X2 tag just above the Reply box :wink:)
gujrichick said:
Hi,

I got 1.32*10^-5 seconds as my time constant.. and I don't understand how I would get a fraction from that or how that would help me answer the other questions.

I get 220 Ω times 60 10-6 F = 1.32 10-2 s
 
oh! I know what I did wrong now, I thought that micro was -9 instead of -6.
Thanks!

but which equations should I use for the other parts? I think for part c I can use C=Q/V and find the total charge. and for d I can do V=IR. But what about part b? Do I use Q=CVe^(-t/RC)? And plug in 1ms for t?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top