What is the maximum of this expression (function)?

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SUMMARY

The discussion focuses on maximizing the expression |\cos^m\theta_1 (c\cos^n\theta_2 + se^{i(\gamma-n\lambda_2)}\sin^n\theta_2) + e^{-im\lambda_1}\sin^m\theta_1 (\pm ce^{-in\lambda_2}\sin^n\theta_2 + se^{i\gamma}\cos^n\theta_2)|^2, where m and n are fixed positive integers greater than or equal to 2, and c, s are real numbers in the interval (0,1). The user proposes that the maximum value of the expression is \max\{c^2, s^2\} but seeks verification of this conclusion. Through calculus, the maximum of the right-hand side of the derived inequality is determined to be \max\{c, s\}.

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Hi,
Will anybody help me to find the maximum of the following expression:

[tex]|\cos^m\theta_1<br /> (c\cos^n\theta_2+se^{i(\gamma-n\lambda_2)}\sin^n\theta_2)+e^{-im\lambda_1}\sin^m\theta_1 (\pm ce^{-in\lambda_2}\sin^n\theta_2+se^{i\gamma}\cos^n\theta_2)|^2[/tex]

where [tex]m,n\ge 2[/tex] are fixed positive integers; [tex]c,s\in (0,1) \mbox{ and } \gamma[/tex] are fixed reals; and we have to maximize with respect to [tex]\theta_1, \theta_2,\lambda_1,\lambda_2[/tex] in the range [tex]0\le\theta_1, \theta_2\le\frac{\pi}{2};~0\le\lambda_1,\lambda_2\le\pi[/tex].

My guess is the answer will be [tex]\max\{c^2, s^2\}[/tex]. But I am unable to prove it (even I don't know if I am correct). Please help me.
 
Last edited:
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Here is my trying... Can anybody verify it, please(if there is any misconception):

We have

[tex] |\cos^m\theta_1<br /> (c\cos^n\theta_2+se^{i(\gamma-n\lambda_2)}\sin^n\theta_2)+e^{-im\lambda_1}\sin^m\theta_1 (\pm ce^{-in\lambda_2}\sin^n\theta_2+se^{i\gamma}\cos^n\theta_2)|[/tex]


[tex] \le\cos^m\theta_1|<br /> (c\cos^n\theta_2+se^{i(\gamma-n\lambda_2)}\sin^n\theta_2)|+\sin^m\theta_1| (\pm ce^{-in\lambda_2}\sin^n\theta_2+se^{i\gamma}\cos^n\theta_2)|[/tex]


[tex] \le \cos^m\theta_1(c\cos^n\theta_2+s\sin^n\theta_2)+\sin^m\theta_1 ( c\sin^n\theta_2+s\cos^n\theta_2)[/tex]

Now by calculus (I mean by differentiating w.r.t. [tex]\theta_1,\theta_2[/tex]) the maximum of the r.h.s. of the last inequality is obtained as [tex]\max\{c,s\}[/tex].
 
Last edited:

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