A Transformation Matrix question

Saladsamurai
Messages
3,009
Reaction score
7

Homework Statement



Find the transformation matrix 'R' that describes a rotation by 120 degrees about an axis from the origin through the point (1,1,1). The rotation is clockwise as you look down the axis toward the origin.

Homework Equations



<br /> \left( \begin{array}{c} A&#039;_x \\ A&#039;_y \\ A&#039;_z \end{array} \right) = <br /> <br /> \left( \begin{array}{ccc} <br /> R_{xx} &amp; R_{xy} &amp; R_{xz} \\ <br /> R_{yx} &amp; R_{yy} &amp; R_{yz} \\<br /> R_{zx} &amp; R_{zy} &amp; R_{zz}<br /> \end{array} \right)<br /> <br /> \left( \begin{array}{c} A_x \\ A_y \\ A_z \end{array} \right)<br /> <br /> <br /> <br />

The Attempt at a Solution



I am just very confused by the wording of the question. I am used to talking about the transformation of a vector... I am not sure what is being transformed here... the coordinate system?

Here is the solution:

Picture1-43.png


I am having a hard time deciphering the problem statement even looking at the solution. It is clear that he wanted us to "swap" axes. But I am not sure exactly what is happening here.
 
Physics news on Phys.org
you can imagine it a few different ways, i would think of it as follows:
- The global coordinate frame does not change.
- The operation is a transformation of a vector within that frame (it maps each vector to a vector).

so imagine the line from the origin to (1,1,1)

Now start with the vector (1,0,0), this will be transformed to (0,0,1).

The global co-ordinate frame doesn't change, but a vector on the x-axis is mapped to a vector on the z axis.

By considering the action on each of the basis vectors it shoudl be pretty startightforward to write down the matrix.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top