Solve Mechanics Problem: Particle with Mass m and Resistive Force of mkv^2

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The discussion revolves around solving a mechanics problem involving a particle projected upwards with an initial speed u, subject to gravity and a resistive force proportional to the square of its velocity. The key equation to derive is v^2 = (g/k + u^2)e^(-2kx) - (g/k). Participants emphasize the need to integrate due to the varying acceleration caused by the resistive force, rather than applying the standard kinematic equations. There is confusion about whether to simplify the force equation, F - mkv - mg = ma, before integration. The conversation highlights the importance of addressing the non-constant acceleration in the problem.
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Homework Statement



A particle with mass m is projected vertically upwards from a point with speed u. THe particle, besides being subjected to gravity, experiences a resistive force of magnitude
mkv^2, with v as its velocity when its height from the point of projection is x and k as a positive constant. Show that

v^2=(\frac{g}{k}+u^2)e^{-2kx}-\frac{g}{k}

Homework Equations





The Attempt at a Solution



F-mkv-mg=ma

using v^2=u^2+2as

v^2=u^2-2gx

thats all i can get
 
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Did you know that the equation v^2 = u^2 + 2as only holds for constant acceleration? You will have to integrate in this case due to the varying acceleration.
 
Fightfish said:
Did you know that the equation v^2 = u^2 + 2as only holds for constant acceleration? You will have to integrate in this case due to the varying acceleration.

thanks , for this , do i integrate

F-mkv-mg=ma ?

am i supposed to get rid of some of the terms here first before i integrate ?
 
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