Find the powers p and q that make this equation dimensionally consistent

  • Thread starter Thread starter swatmedic05
  • Start date Start date
AI Thread Summary
To determine the powers p and q for the equation A=V^p t^q, one must first identify the dimensions of acceleration (A), velocity (V), and time (t). Acceleration has dimensions of length over time squared [L][T^-2], while velocity is length over time [L][T^-1], and time is simply [T]. By equating the dimensions from both sides of the equation, it becomes clear that the left side (LT^-2) must match the right side (L^p T^(-p+q)). This leads to a system of equations that can be solved for p and q, confirming the dimensional consistency of the equation. The discussion emphasizes the importance of understanding dimensional analysis in physics.
swatmedic05
Messages
42
Reaction score
0
Acceleration is related to velocity and time by the following expression: A=V^p t^q

Find the powers p and q that make this equation dimensionally consistent.
 
Physics news on Phys.org
So what dimensions are A, V and t ?

When you get that, then equate exponents.
 
I new to physics I still don't get what I have to do
 
swatmedic05 said:
I new to physics I still don't get what I have to do

Alright then. Let's start simple.

What are the units for acceleration (A)?

What are the units for velocity (V)?

What are the units for time (t) ?
 
A= [l]/[t]^2
v= [l]/[t]
t=[t]
 
swatmedic05 said:
A= [l]/[t]^2
v= [l]/[t]
t=[t]

Good. So in A=Vptq, on the left side we have

LT-2

and on the right we have

(LT-1)p(T)q

What does the right side give?
 
I just got it now... Thank you for explaining it better to me. I appreciate all your help
 
Back
Top