Find the powers p and q that make this equation dimensionally consistent

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Homework Help Overview

The discussion revolves around finding the powers p and q in the equation A=V^p t^q to ensure dimensional consistency, focusing on the relationships between acceleration, velocity, and time.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the dimensions of acceleration, velocity, and time, and how to equate the exponents to achieve dimensional consistency.

Discussion Status

The conversation has progressed with participants clarifying the units involved and attempting to equate the dimensions on both sides of the equation. Some participants express confusion, while others provide explanations to facilitate understanding.

Contextual Notes

There is an indication that some participants are new to physics, which may affect their grasp of the concepts being discussed. The discussion includes a focus on understanding the units of measurement for acceleration, velocity, and time.

swatmedic05
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Acceleration is related to velocity and time by the following expression: A=V^p t^q

Find the powers p and q that make this equation dimensionally consistent.
 
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So what dimensions are A, V and t ?

When you get that, then equate exponents.
 
I new to physics I still don't get what I have to do
 
swatmedic05 said:
I new to physics I still don't get what I have to do

Alright then. Let's start simple.

What are the units for acceleration (A)?

What are the units for velocity (V)?

What are the units for time (t) ?
 
A= [l]/[t]^2
v= [l]/[t]
t=[t]
 
swatmedic05 said:
A= [l]/[t]^2
v= [l]/[t]
t=[t]

Good. So in A=Vptq, on the left side we have

LT-2

and on the right we have

(LT-1)p(T)q

What does the right side give?
 
I just got it now... Thank you for explaining it better to me. I appreciate all your help
 

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