Formal definition of what the symbol 0

AI Thread Summary
The discussion centers on the formal definition of the factorial symbol, specifically addressing why 0! equals 1. It is explained that this definition is consistent with the factorial function for all positive integers and is widely accepted in mathematics. Two main arguments are presented: one explains that 0! represents the number of ways to arrange zero items, which is one way, and the other relates it to the gamma function, where 0! is defined as 1. The importance of understanding the definition of factorial is emphasized, as it underpins the reasoning for why 0! is defined this way. Overall, 0! = 1 is a foundational concept in combinatorics and mathematical functions.
abc
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hellooooooooooo everybody !
can anyone please prove the following :
0! = 1

cheers abc
 
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i really didn't understand that ... could u please reexplain it in an easier way ... and i will be so thankful to u
cheers
abc
 
Well, I guess that means as a FAQ definitive answer it is defective. However I don't think that you've actually spent sufficiently long considering what the definition of factorial is. So, why don't you write what you understand factorial to mean; it may at least improve the faq type answer.

That 0!=1 is pretty much a formal definition of what the symbol 0! means and it is consistent with n! for all positive n.
 
dear matt
as u said i have just today studied the factorial at class ... and when the teacher explained the definition of ...then said that 0!=1 ... it was weird to me and i didn't have the time to ask him about it ... so if u would explain ... please start from the zero ... so i could understand well
thanx
abc
 
that doesn't tell me what you think factorial means, in fact it appears that you 've not remembered the definition of n! so if you've not remembered the definition of n! for positive n how can you expect to understand why 0!=1? get your notes from class and look at the definition, and then post it so we can see what your working from.
 
do u mean this
n! = n(n-1 ) (n-2 ) ...... 3*2*1
 
Let's go with that. That doesn't tell us what 0! is, so we can simply declare 0! to be 1, and there is no problem there at all. this is common, and widely accepted. factorials of negative numbers aren't defined. this then allows us to say that n!=n*(n-1)! for all n greater than or equal to 1 (and that 0!=1).
 
You could use either of these arguments:

(1) The factorial tells how many ways there are of arranging N items. You can arrange 5 items in 5! ways. There is exactly one way of arranging NO items or 0! ways.

(2) The factorial is a special case of the gamma function with x! = \Gamma (x+1).
 
  • #10
You don't "prove" that 0!= 1, any more than you "prove" that 3!= 3*2*1. That's the definition of 0!. You could ask WHY that is the definition and the best answer is that it's because so many formulas involving n! also work for n= 0 as long as 0! is defined to be 1.
 
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