Reduction of Gravity: Effects on Object Motion

AI Thread Summary
If Earth's gravity were 1/6 of its normal value, objects thrown upwards would indeed stay in the air longer, but not exactly six times longer. The relationship involves kinematic equations, specifically t=(2v)/a, where time (t) is inversely proportional to acceleration (a). For lower gravity, the time of flight increases due to reduced downward acceleration. The discussion emphasizes the importance of understanding basic physics principles and equations to derive the answer. Overall, the conclusion is that while the time increases, the exact factor is determined through calculations rather than a simple multiplication.
Zeteg
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Okay, if...

The Earth's gravity was 1/6 of what it normally is, then would I be correct to assume that objects being thrown up with the same velocity will stay in the air 6 times as long? If not, what's the relationship? Thanks.
 
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Have you heard of F = ma? Have you done some calculus? If the answer to both question is yes, then can you see how you might be able to derive some equations which you could use to work out the answer to your question yourself?
 
Nereid said:
Have you heard of F = ma? Have you done some calculus? If the answer to both question is yes, then can you see how you might be able to derive some equations which you could use to work out the answer to your question yourself?
Methinks the answer is "no"

Zetig, is this a homework question? OR are you just curious?

If just curious, then yes, the time is increase six-fold. IF homework, you would need to prove it. It can be done with algebra, and this kind of problem is common in introductory physics.
 
Last edited:
Well, I answered it already with yes :P
Thanks for the help. And yes, I did prove it, I'm pretty sure.
 
That's good. FYI, the simplist trick is to use the kinematics equation d=vt + 1/2at^2 (where v = initial velocity). When the ball comes back to your hand, d = zero. The formula simplifies to t=(2v)/a . So t is inversely proportional to a.
 

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