Discovering Exponential Functions: 2 Equations for y=3 with y-intercept of 5

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To create two equations for an exponential function with a y-intercept of 5 and an asymptote at y=3, one equation provided is y=2^(x+1) + 3. To find a second equation, the suggestion is to reflect the graph across the y-axis by replacing "x" with "-x". This transformation yields the second equation, which maintains the same characteristics. Both equations represent the same exponential function with the specified properties. Understanding these transformations is crucial for working with exponential functions.
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I need to write 2 equations that represent the same exponential function with a y-intercept of 5 and an asymptote at y=3. I got y=2^(x+1) + 3 but I don't know how to find the second equation. Can someone please explain this to me. Thanks.
 
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Since the y- intercept is at (0, 5) and the asymptote, y= 3, is symmetric about the x-axis, try "reflecting" that graph in the y-axis. That is, replace your "x" with "-x".
 
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