Complex Trigonometric Solutions

AI Thread Summary
To solve the equation x^7 = 1, the discussion focuses on finding all complex solutions using trigonometric identities. The approach involves expressing the solutions in the form Rcis(θ) and simplifying to find that cos(7θ) = 1 and sin(7θ) = 0. The key step is solving 7θ = 0 + 2πn for θ, leading to the seventh roots of unity. The solutions are then plotted on the unit circle, confirming the relationship between the roots and their positions in the complex plane. The final solutions represent the angles θ = (0 + 2πn)/7 for n = 0, 1, 2, ..., illustrating the concept of roots in complex numbers.
Bogrune
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Homework Statement


2.) Solve
x7=1
I am to solve for all the solutions to this polynomial, including the complex solutions using trigonometry. I'm supposed to plot my solutions on the unit circle, with the x-axis being the real axis, and the y-axis being the imaginary (or complex) axis.

Homework Equations


I'm supposed to use the following Identities to solve the equation: Rcis, meaning: R (real) times cosine + i(complex) sine.
cisn(θ)=cis(nθ)

The Attempt at a Solution


I've numbered my steps taken in order:

x7=1
1.)(Rcisθ)7=1

2.)Rcis(θ)7=1

3.)cis7(θ)=1

4.)cis(7θ)=1

5.)cos(7θ) + isin(7θ)=1 + i0

5a.) cos(7θ)=1
7θ= cos-1(1)
7θ= 0 + 2πn

5b.) sin(7θ)=0
7θ= sin-1(0)


And that's where I got stuck.
 
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Bogrune said:

I've numbered my steps taken in order:

x7=1
1.)(Rcisθ)7=1

2.)Rcis(θ)7=1

3.)cis7(θ)=1



Do you have a "relevant equation" that explains why you can get rid of the R. (I don't use the cis notation, myself, so I'm not sure what you are supposed to say)

4.)cis(7θ)=1

5.)cos(7θ) + isin(7θ)=1 + i0

5a.) cos(5θ)=1

it should say cos(7θ) , of course

7θ= cos-1(1)
7θ= 0 + 2πn

5b.) sin(7θ)=0
7θ= sin-1(θ)


It should say sin-1(0). (The solution won't add any new information because it will also imply that 7θ= 0 + 2πn


And that's where I got stuck.

Solve 7θ= 0 + 2πn for θ

Let n = 0,1,2... and you'll come back to where you started when n/7 = 1
 
I simply got rid of the "R" because it's not really a variable. I forgot to mention that "R" simply stands for "real", because of the fact that cosθ lies on the x-axis (or the real axis, in this case) and isinθ lies on the y (imaginary)-axis.
And sorry about the typos, I make those pretty often! ^^;
Solve 7θ= 0 + 2πn for θ

Let n = 0,1,2... and you'll come back to where you started when n/7 = 1
Oh, I think I see it now. So I plot those on the unit circle as θ= (0 +2πn)/7, and I get my final solution, right?

Though, thanks for the help!
 
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Yes, that's right. You are plotting what are called "the seventh roots of unity". In the complex numbers, 1 has 2 square roots, 3 cube roots, 4 fourth roots, etc.
 
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