Circular motion Problem Can Anyone Help?

AI Thread Summary
A physics problem involves a crate of mass 96 kg on a truck with a static friction coefficient of 0.14, moving at a speed of 2.9 m/s. To determine the smallest radius of curvature, the formula R = mv^2/(μg) is applied, where g is the acceleration due to gravity (9.8 m/s²). Substituting the values yields a radius of curvature of 62.65 m. This calculation ensures that the centripetal force does not exceed the frictional force. Understanding this concept is crucial for solving similar problems in physics.
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I have an Ap Physics Class and my teacher doesn't have time to help me and i was wondering if anyone could help me with this problem.

A crate of mass 96 kg is loaded onto the back of a flatbed truck. The coefficient of static friction between the box and the truck bed is 0.14. What is the smallest radius of curvature, R, the truck can take, if the speed with which it is going around a circle is 2.9 m/s?
 
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For the crate to go around the circle, its centripedal force must be less than or equal to the frictional force. By using this info, apply the formula (mv^2)/R then it's done.
 


Hello! I understand that you are struggling with a circular motion problem in your Ap Physics class and your teacher is unable to assist you. I would be happy to help you with this problem.

First, let's break down the information given in the problem. We know the mass of the crate (96 kg), the coefficient of static friction (0.14), and the speed of the truck (2.9 m/s).

To find the smallest radius of curvature, we will use the formula: R = mv^2/μg, where m is the mass, v is the speed, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the values given, we get R = (96 kg)(2.9 m/s)^2/(0.14)(9.8 m/s^2) = 62.65 m.

Therefore, the smallest radius of curvature the truck can take is 62.65 m. I hope this helps you understand the problem better. If you have any further questions or need clarification, please don't hesitate to ask. Good luck with your Ap Physics class!
 
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