Centripetal Force in Uniform Centripetal Motion: Direction?

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In uniform circular motion, both centripetal acceleration and centripetal force point towards the center of the circular path. The net force acting on an object in this motion must also direct towards the center to maintain circular movement, as dictated by Newton's second law. The term "centripetal" literally means "towards the center," reinforcing this relationship. If an object is twirled, the force measured by a spring scale reflects the tension exerted, with the inward component contributing to the centripetal force. Overall, a non-zero net force is essential for maintaining circular motion.
UrbanXrisis
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in uniform centipetal motion, the centipetal accleration points towards the center, what about the centipetal force? What direction does this force point?
 
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Acceleration is always in the direction of the unbalanced force. The centrifugal force (inertia) wants the motion to continue its direction at any given moment. However, the centripetal force keeps the motion and force towards the center.
 
so the centripetal force acts towards the center too?
 
UrbanXrisis said:
so the centripetal force acts towards the center too?
Of course. As you noted, an object in uniform circular motion is centripetally accelerated. And, by Newton's 2nd law (\vec{F} = m\vec{a}), the net force and acceleration point in the same direction: towards the center.

By the way, the word "centripetal" means "towards the center". :smile:
 
So if I was twriling a ball connected to a spring scale. And there was enough air friction to make the net force=0. Then what would be the relationship between the force the spring scale reads vs the centripetal force?
 
If the net force were zero, then the ball would not be twirling in a circle. :smile: For the ball to move in a circle, there must be a non-zero net force on it; if the ball is moving at a constant speed, then that net force must point towards the center of the circle.

If you twirl a ball connected to a spring scale, then the spring scale reads the tension you are exerting on the ball. The component of that force acting towards the center will contribute to the centripetal force. (But other forces, such as gravity, may also contribute to the centripetal force.)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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