Simple Integral but unknown method

[EternityMech]

x+1/(x+2)(x+3) = A/x+2 +B/x+3

how do u calculate A and B ?

nevermind i got it thanks.

 

[mathman]

R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}

Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1