Doped semiconductor-to find the resistance?

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The discussion centers on calculating the resistance of an extrinsic semiconductor with a doping concentration that varies along its length. The resistance formula R is initially misapplied, leading to confusion about whether it should depend on the position x due to the varying doping concentration. A participant suggests using a differential resistance approach, dR, for a short length dx, which incorporates the varying doping concentration. This method involves integrating the expression to find the total resistance. The integration approach is recognized as a helpful solution to the problem.
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Homework Statement


An extrinsic semiconductor sample of cross section A and length L is doped in such a way that the doping concentration varies as Nd=N0 Exp(-x/L)
Assume that mobility μ of the majority carriers remain constant.What is the resistance of the sample?

Homework Equations


σ=neμ
ρ=1/σ
R=Lρ/A=L/(Aμen)

The Attempt at a Solution


In the eqn n is the free electron concentration.
I thought this will be eqal to doping concentration.
then,R = L/(AμeNoExp(-x/L))
But this is not the right answer.

Can this resistance be varrying with x since doping concentration depend on x?

Thanks.
 
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humanist rho said:

Homework Statement


An extrinsic semiconductor sample of cross section A and length L is doped in such a way that the doping concentration varies as Nd=N0 Exp(-x/L)
Assume that mobility μ of the majority carriers remain constant.What is the resistance of the sample?

Homework Equations


σ=neμ
ρ=1/σ
R=Lρ/A=L/(Aμen)

The Attempt at a Solution


In the eqn n is the free electron concentration.
I thought this will be equal to doping concentration.
then,R = L/(AμeNoExp(-x/L))
But this is not the right answer.

Can this resistance be varying with x since doping concentration depend on x?

Thanks.
The resistance, dR, for a very short length, dx, of semi-conductor is \displaystyle dR=\frac{dx}{A\mu N_0 e^{-x/L}}

Integrate that .
 
That was really helpful.Thank you.
 
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