aisha said:
why did we only look at the fraction and not the 1 whole rotation? If it wasnt one would we still only look at the fraction rotation? Basically now I need some pointers on how to sketch these principal angles, please help thanks
Okay,you're asked for an angle that should be between 0 and 360° which is less than a rotation okay??(The case 360° is noninteresting,as it is the same with 0°).So the integer number of rotations (the one that is at the left of the fraction line) is not interesting since it is a multiple of 360°,and therefore is equivalent with 0 rotations (or with the 0° angle).
In case of the negative angles,u must make that rotation of the arm clockwise,while in the case of positive angles,u'll have to make it anticlockwise (trigonometric sense).Any integer number of rotations (no matter the sense) is equivalent to 0° so therefore it's not relevant.
For angles in the negative interval (-360°,0°),u must find the principal angle,which must be between 0° and 360°.The transformation is achived simply by adding 360°.
Example:Consider the angle of -4696°.Divide it by 360°.U'll get:
1 rotation anticlockwise -------------------> +360°
1 rotation clockwise------------------------>-360°
x rotations clockwise------------------------>-4696°
x=\frac{-4696}{-360}=13\frac{16}{360} rotations clockwise.
Again,neglect the integer number of rotations (no matter the sense) a,d concentrate upon the fraction.
1 rotation clockwise-------------------->-360°
16/360 rotations clockwise--------------> y°
U find y=-16°.However,u need the positive angle correseponding to -16°.And that is
Pos.ang.=-16+360=+344
,which is in the interval [0,360°].
Daniel.