Kinetic energy of two protons to create a meson?

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Homework Statement


This one stumped me a little
Two protons are heading toward each other with equal speeds.
What minimum kinetic energy must each have if a ∏2 meson is to be created in the process?

Homework Equations


E=mc2
p+p→p+p+∏2
E=Ek-mc2 ? not sure if I got this right or even useful

The Attempt at a Solution



E=mc2
=135MeV
=135x106x1.6x10-19
=2.16x10-11
 
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actually I worked it out, it was correct, they just wanted it in MeV
 

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