Work and frequency caused by mutual potential energy

AI Thread Summary
The discussion revolves around calculating the work required to separate a Li+ ion and an I- ion based on their mutual potential energy, represented by the equation U(r)=(-Ke^2/r)+(A/r^10). Participants express confusion about the unknown constant A, which is necessary for solving the problem, particularly in determining the work and frequency of vibrations for the Li+ ion. One user successfully found A by taking the derivative of U(r) and setting it to zero at the equilibrium distance of 2.4 Angstroms. However, challenges arise in calculating the second derivative for the spring constant due to the small scale of the values involved. Suggestions include using different units or scientific notation to manage the calculations effectively.
phys17
Messages
2
Reaction score
0
Hi everyone,

Homework Statement


Here is the question:
The mutual potential energy of a Li+ ion and an I- ion as a function of their separation r is expressed fairly well by the equation U(r)=(-Ke^2/r)+(A/r^10), where the first term arises from the Coulomb interaction, and the values of its constant are:

K= 9x10^9 N-m^2/C^2, e=1.6x10^-19 C

The equilibrium distance rnot between the centers of these ions in the LiI molecule is about 2.4 Angstrom. On the basis of this info,

(a) How much work in eV must be done to tear these ions completely away from each other?

(b) Taking the I- ion to be fixed b/c it is so massive, what is the frequency in Hz of the Li+ ion in vibrations of very small amplitude? Take the mass of Li+ as 10^/26



The Attempt at a Solution



I used the U(r) formula to find the work, but how can you find the work without knowing what A is?
For part b, i found the second derivative of the U(r) function to get the value of the spring constant, k. Again, how do we know what the value of A is?

Thanks for any and all help!
 
Physics news on Phys.org
Hi phys17,

Never in all my years have I encountered a 1/r^10 term in a potential. Am I reading this correctly - you mean 'one over r to the power of ten'? I guess there's nothing actually wrong with that - you can write down any wild potential you want - but I don't think anyone here is going to be able to guess what that term could possibly be or what the 'A' is without some more information. That being said, your ideas on how to deal with the vibrations via a spring constant are very good - well done, I think that is correct! Is it possible that your instructor meant for you to leave things in terms of A? Because with the information interpreted literally and as given, that's the best you can do. Sorry I don't have more insight, but I think we need some more information or your instructor needs to explain what this term is supposed to be.

Hope this helps,
Bill Mills
 
Last edited by a moderator:
phys17 said:
Hi everyone,

Homework Statement


Here is the question:
The mutual potential energy of a Li+ ion and an I- ion as a function of their separation r is expressed fairly well by the equation U(r)=(-Ke^2/r)+(A/r^10), where the first term arises from the Coulomb interaction, and the values of its constant are:

K= 9x10^9 N-m^2/C^2, e=1.6x10^-19 C

The equilibrium distance rnot between the centers of these ions in the LiI molecule is about 2.4 Angstrom. On the basis of this info,

(a) How much work in eV must be done to tear these ions completely away from each other?

(b) Taking the I- ion to be fixed b/c it is so massive, what is the frequency in Hz of the Li+ ion in vibrations of very small amplitude? Take the mass of Li+ as 10^/26

The Attempt at a Solution



I used the U(r) formula to find the work, but how can you find the work without knowing what A is?
For part b, i found the second derivative of the U(r) function to get the value of the spring constant, k. Again, how do we know what the value of A is?

Thanks for any and all help!

Welcome to PF :smile:

Here's a hint: what must be true about U(r) at the equilibrium position r=rnot=2.4Å?
billVancouver said:
Hi phys17,

Never in all my years have I encountered a 1/r^10 term in a potential.
I imagine it's an approximation for when then two ions are close together. Somewhat akin to the 1/r12 term in the Lennard-Jones potential typically used for neutral atoms.
Am I reading this correctly - you mean 'one over r to the power of ten'? I guess there's nothing actually wrong with that - you can write down any wild potential you want - but I don't think anyone here is going to be able to guess what that term could possibly be or what the 'A' is without some more information.
Don't forget, we are given the equilibrium position.
That being said, your ideas on how to deal with the vibrations via a spring constant are very good - well done, I think that is correct! Is it possible that your instructor meant for you to leave things in terms of A? Because with the information interpreted literally and as given, that's the best you can do. Sorry I don't have more insight, but I think we need some more information or your instructor needs to explain what this term is supposed to be.

Hope this helps,
Bill Mills
 
Thanks so much, guys!

I figured out part a today. To find A, I found the derivative of U(r), set it equal to 0 and then solved for A, since that is the unknown. From there, it's easy to find the work - just substitute all the numbers in.

I ran into trouble for part b. Since the spring constant is the second derivative of U(r), I evaluated at that second derivative. BUT, 2.4 Angstrom converted to meters is a really small value, so when I do A/r^10, I just get 0.
 
There are a couple of way around that, that I can think of:

1. Use eV and Å for units, instead of J and m. The numbers should be closer to "regular size" that way, i.e. neither extremely small or extremely large in magnitude.

or

2. Work in scientific notation. Use the calculator to work the between-1-and-10 part of the numbers, and use pen and paper to work the 10xxx's

If you're still stuck, by all means post your work here. Otherwise these suggestions are just a stab in the dark at helping you out.

EDIT added: #3 - use Google as your calculator, it can handle 1/(2.4Å)10:

http://www.google.com/#hl=en&sclien....,cf.osb&fp=3226d37ade666d03&biw=1280&bih=638
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top