Figuring out what image distance (lens and mirror) formula to use?

AI Thread Summary
The discussion focuses on two derived equations from the lens formula 1/f = 1/d0 + 1/di. The first equation presented, 1/di = 1/d0 - 1/f, is identified as incorrect, while the second equation, di = d0(f) / (d0 - f), is a valid rearrangement of the lens formula. Participants emphasize the importance of understanding the physics behind these equations rather than memorizing them. A suggestion is made to clarify the first equation by reversing the right-hand side to 1/di = 1/f - 1/d0. Overall, the conversation encourages practicing algebra and grasping the underlying concepts of optics.
Clomo4star
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I was practicing homework and I came across these two derived equations from 1/f=1/d0+1/di
1st one 1/di=1/d0-1/f
2nd one di=d0(f)/d0-f
How do distinguish which one to use? and how did they get that derivation for the 2nd equation?
 
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I wouldn't worry about memorizing the different forms of the equations to use for which situation, focus on understanding the physics.

Note - the second one is just what happens to the lensmakers formula if you solve it for di. The first one is incorrect.
 
Clomo4star said:
I was practicing homework and I came across these two derived equations from 1/f=1/d0+1/di

1st one 1/di=1/d0-1/f

Are you sure the right-hand side wasn't reversed, that is,

$$\frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o}$$

2nd one di=d0(f)/d0-f

This is just a re-arrangement of your first equation. It's good algebra practice. First, get the 1/di all by itself on the left as in my equation above. Can you see where to go from there? (hint: how do you add or subtract fractions?)
 
Oh yeah sorry oops I was just wondering about the 2nd one.
 
No worries - did you have a go at the derivation yet? How did you get on?
 
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