Finding Velocity on a Position/Time Graph

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To find velocity on a position/time graph, it's essential to calculate the slope correctly. The slope represents velocity, and for a straight line, it should remain constant. The formula Vf-Vi/Tf-ti is meant for calculating average velocity, not acceleration. If different calculations yield varying results, it indicates a miscalculation in determining the slope. Ensuring consistent points are used from the graph will help achieve the correct velocity value.
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Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
 
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Try to post the graph so we can see it. Also, if your v is velocity, you are dividing a velocity change by an elapsed time. That gives acceleration. If you want velocity, divide displacement by time.
 
5pirit said:
Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
Hello 5pirit. Welcome to PF !

What is the slope of that line?
 
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