Magnetic Forces on Moving Charges True or False

AI Thread Summary
The discussion centers on the behavior of a charged particle moving through a magnetic field and the relationships between magnetic force, velocity, acceleration, and the magnetic field itself. Participants analyze four statements regarding these relationships, with initial answers being debated and corrected. Key points include the understanding that the magnetic force is always perpendicular to both the velocity and the magnetic field, and that acceleration is parallel to the magnetic force, not necessarily perpendicular to velocity. The right-hand rule is suggested as a method to visualize the direction of forces and motion. Ultimately, the correct answers to the statements are clarified as TFTT.
devilaudy
Messages
7
Reaction score
0

Homework Statement



Consider a charged particle moving with velocity v through a magnetic field B. Answer True or False.

1) The magnetic field B is always perpendicular to the acceleration a of the particle.
2) The magnetic force F is always perpendicular to the acceleration a of the particle.
3) The acceleration a of the particle is always perpendicular to the velocity v.
4) The force F exerted by the magnetic field is always perpendicular to the velocity v.

Homework Equations



F = qv x B (cross product, magnetic force on a moving charged particle).

The Attempt at a Solution



I tried 1) false 2) true 3) false 4) true and FFFT, but it was wrong. I was sure about my first answer since the magnetic force is always perpendicular to B and V.
 
Physics news on Phys.org
hi devilaudy! :smile:

think about (3) again …

what does the magnetic force equation mean? :wink:
 
tiny-tim said:
hi devilaudy! :smile:

think about (3) again …

what does the magnetic force equation mean? :wink:

Thank you for answering! I was not really thinking about the acceleration, I thought it would have the same direction as the velocity of the particle! But would it be perpendicular to its motion? Then the acceleration would be parallel to the force exerted by the magnetic field, so the answers would be TFTT. I am not sure if I am getting it right...
 
^ That looks right to me.

It's easier to think about this with a concrete example. Suppose the particle is positively charged, moving to the right, and the magnetic field points into the page/screen. Use the right hand rule to figure out the direction of the force. What kind of motion does the particle undergo?
 
Last edited:
hi devilaudy! :smile:

(just got up :zzz:)
devilaudy said:
Then the acceleration would be parallel to the force exerted by the magnetic field

that's right … good ol' Newton's second law … acceleration is always parallel to force! :wink:

(so in a constant magnetic field, everything goes in a circle …*the faster it goes, the larger the circle … see if you can prove that)
, so the answers would be TFTT. I am not sure if I am getting it right...

i think you're confusing field with force :redface:
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...

Similar threads

Back
Top