Unit Vectors and Vector Components

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In a Cartesian coordinate system, the x- and y-components of a force vector F can be expressed as F_x = |F| cos(θ) and F_y = |F| sin(θ). When determining the unit vector for F, the x- and y-components of this unit vector correspond to cos(θ) and sin(θ), respectively. This is achieved by dividing each component by the magnitude of the vector |F|. Understanding this relationship is essential for accurately breaking down vectors into their components. The discussion confirms that the unit vector components align with the trigonometric functions based on the angle θ.
Alexrey
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I remember in my first year physics classes, when dealing with a force F we would find the vector's x- and y-components using F_x=r cos(θ) and F_y=r sin(θ) I also remember learning in my mathematics classes about unit vectors, but cannot seem to remember using them to break vectors down into their respective x- and y-components. As such, I thought I'd ask this question: Am I correct in thinking that when using a Cartesian coordinate system to describe a force F, if we find the unit vector for F, are the x- and y- components of this unit vector equivalent to cos(θ) and sin(θ) respectively?
 
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Alexrey said:
I remember in my first year physics classes, when dealing with a force F we would find the vector's x- and y-components using F_x=r cos(θ) and F_y=r sin(θ) I also remember learning in my mathematics classes about unit vectors, but cannot seem to remember using them to break vectors down into their respective x- and y-components. As such, I thought I'd ask this question: Am I correct in thinking that when using a Cartesian coordinate system to describe a force F, if we find the unit vector for F, are the x- and y- components of this unit vector equivalent to cos(θ) and sin(θ) respectively?
Yes, assuming θ is the angle that F makes with the x-axis.

Think about it.
Fx = |F| cos(θ)
Fy = |F| sin(θ)

To get unit vectors, divide each of the above by its magnitude, |F|.
 
Great, thank you.
 
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