Boyle's law and constant temperature

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Boyle's law asserts that the product of pressure and volume of a gas remains constant at a fixed temperature. When pressure increases, the volume must decrease proportionally, provided the temperature does not change. To maintain a constant temperature while increasing pressure, heat must be allowed to escape, often facilitated by conducting the experiment in a heat bath, such as a mixture of ice and water. This ensures that the gas remains in thermal equilibrium with its surroundings. Understanding these principles is crucial for accurately applying Boyle's law in practical scenarios.
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Boyle's law states that the product of the pressure and the volume of a gas is
Constant at a constant temperature, that means if pressure increase two times the volume decrease to half it's value "as long as the temperature is constant". How is the pressure increased and the temperature is kept constant, since increasing pressure involves doing work on the gas, shouldn't the temperature increase?
 
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I think in reality this experiment can only be done very slowly so that the gas roughly remains in temperature equilibrium with its surroundings.
 
ElmorshedyDr said:
Boyle's law states that the product of the pressure and the volume of a gas is
Constant at a constant temperature, that means if pressure increase two times the volume decrease to half it's value "as long as the temperature is constant". How is the pressure increased and the temperature is kept constant, since increasing pressure involves doing work on the gas, shouldn't the temperature increase?

Yes, you right. You're doing work on the gas so you must allow an equal amount of heat to come out so the temperature may remain constant. That's why that experiment is done in a heat bath of constant temperature. A mixture of ice and water works well.
 
PV/T general gas law, PV Boyles law.
P-pressure
V-volume
T-temp

If you increase your pressure you increase your volume of gas
 
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