Calculate heat released in the reaction

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The discussion focuses on calculating the heat released during a specific chemical reaction involving substances A, B, C, and D, with given combustion enthalpies. The reaction proceeds at constant volume and is first-order with respect to A, which decreases to half its initial amount in 69.3 seconds. The initial calculation of ΔH for the reaction was determined to be 2400 cal/mol, but the user encountered confusion regarding the correct interpretation of ΔQ. The user attempted to derive ΔQ using the relationship ΔQ = ΔH - Δng RT but found discrepancies in their results. Clarification is sought on calculating ΔQ per mole accurately.
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Homework Statement


All the substances involved in the reaction given below can undergo combustion reaction and their combustion enthalpies at 300K are given below,
2A(g)+B(g) ----> 3C(g) + D(g)
Given: ΔH A = -1000cal/mol ΔH B= -2000cal/mol ΔH C=-500 cal/mol ΔH D = -100 cal/mol
If the reaction occurs at constant volume at 300K and the reaction obeys first order with respect to A and if A reduces to half its initial amount in 69.3 sec, then calculate

1) heat released when 2*10-3 mole of A has reacted at 300K(in cal)

2) rate at which heat is released initially, if initially 1mol of A is present.


The Attempt at a Solution



ΔH of rxn = 2400 cal/mol
ΔH = ΔU + Δng RT
Since the reaction occurs at constant volume ΔQ = ΔU
ΔQ = ΔH - Δng RT

Substituting appropriate values , I get ΔQ = 1800 cal/mol. But this is not the correct answer.
 
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Where does it ask for ΔQ PER MOLE??
 
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