Einstein's Derivation of E=mC2: English Translation

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Einstein's derivation of the equation E=mc² is rooted in his 1905 papers on special relativity, specifically the second article published in Annalen der Physik. The integral used in the derivation is ∫^c_0{P dv}, where P = mvγ and γ = 1/√(1 - (v/c)²). This mathematical approach confirms the relationship between energy and mass, establishing a foundational principle in physics. For an English translation of Einstein's original work, refer to the provided links.

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¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.
 
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Iraides Belandria said:
¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.

See
http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf
(there is translated in english the second article Einstein published in Annalen der physik about special relativity -thanks dex, i missed last- in german)
 
Last edited:
It was his second article on SR in 1905 and the IV-th overall in that year.

http://www.aip.org/history/einstein/chron-1905.htm

Daniel.
 
thanks Rebel and dextercioby for the required information
 
You can simply take this integral and you'll get E = mc^2

\int^c_0{P dv} ;

where P = mv\gamma

and \gamma = \frac{1}{\sqrt{1 - (\frac{v}{c})^2}}

\int^c_0 {\frac{mv}{\sqrt{1 - (\frac{v}{c})^2}} dv = mc^2
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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