Einstein's Derivation of E=mC2: English Translation

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    Derivation E=mc2
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Discussion Overview

The discussion centers on the derivation of the equation E=mc² by Einstein, specifically seeking an English translation of his original paper. Participants explore the historical context of the derivation and share resources related to Einstein's work on special relativity.

Discussion Character

  • Exploratory, Historical, Technical explanation

Main Points Raised

  • Some participants inquire about the method Einstein used to derive E=mc² and seek an English translation of his original paper.
  • One participant provides a link to a translated version of Einstein's second article on special relativity, noting its significance in understanding the derivation.
  • Another participant references the chronological context of Einstein's publications in 1905, indicating that this was his second article on special relativity.
  • A later reply presents a mathematical approach to deriving E=mc² using integrals, suggesting a specific integral involving momentum and velocity.

Areas of Agreement / Disagreement

Participants generally agree on the importance of the historical context and the availability of translations, but there is no consensus on the derivation method, as multiple approaches are presented.

Contextual Notes

The mathematical derivation presented relies on specific assumptions about momentum and relativistic effects, which may not be universally accepted or fully detailed in the discussion.

Iraides Belandria
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¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.
 
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Iraides Belandria said:
¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.

See
http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf
(there is translated in english the second article Einstein published in Annalen der physik about special relativity -thanks dex, i missed last- in german)
 
Last edited:
It was his second article on SR in 1905 and the IV-th overall in that year.

http://www.aip.org/history/einstein/chron-1905.htm

Daniel.
 
thanks Rebel and dextercioby for the required information
 
You can simply take this integral and you'll get E = mc^2

\int^c_0{P dv} ;

where P = mv\gamma

and \gamma = \frac{1}{\sqrt{1 - (\frac{v}{c})^2}}

\int^c_0 {\frac{mv}{\sqrt{1 - (\frac{v}{c})^2}} dv = mc^2
 

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