Chain and Elastic string problem

AI Thread Summary
A uniform chain of length L hangs from an elastic string, which stretches by L when in equilibrium. The problem involves determining the distance from the lower end of the chain to cut it so that the upper end strikes the ceiling. The force constant 'k' of the string is derived from the equilibrium condition, leading to the equation k = mg/L. By applying conservation of energy, the calculation shows that cutting the chain at a distance of (3/4)L from the bottom allows the remaining chain to reach the ceiling. The reasoning and calculations provided are validated as correct.
Vibhor
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Homework Statement



A uniform chain of length L hangs from an elastic string of natural length L. The upper end of the string is connected with the ceiling .When the system is in equilibrium , the string stretches by an amount L .At what distance from the lower end of the chain ,the chain should be cut so that upper end of chain just strikes the ceiling?

Homework Equations





The Attempt at a Solution



'k' is the force constant of the string and m is the mass of the chain.

From equilibrium condition kL = mg → k=mg/L

Suppose the chain is cut a distance 'x' from below .

Applying COE , (1/2)kL2 = (m/L)(L-x)g(2L)

This gives x= (3/4)L .

Is it right ?

Many Thanks
 
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You have argued that the energy stored in the string needs to be enough to throw the remaining mass through a height 2L ... that is well reasoned, well done.
 
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