Linewidths - Frequency and Wavelength

AI Thread Summary
The discussion centers on the relationship between line widths in frequency and wavelength, highlighting a common confusion. It is noted that a broader spread of frequencies should correspond to a broader spread of wavelengths. The mathematical relationship derived from the equation c = fλ indicates that changes in frequency (df) and changes in wavelength (dλ) have opposite signs. This leads to confusion about why a positive change in frequency results in a negative change in wavelength. The conversation reassures that understanding this relationship is achievable with confidence in mathematical principles.
Naz93
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Hi,

Probably a really stupid question... but I'm confused about how to relate a line width in frequency to one in wavelength. To me it seems obvious that if there's a broader spread of frequencies, there must be a broader spread of wavelengths, and vice versa - after all, the line is broader.

But... if you relate Δf and Δλ mathematically (f is frequency, since there was no nu on the quick symbols list):

c = fλ

f = c/λ

df/dλ = -c/(λ^2)

so df = dλ * (-c/(λ^2))

I.e. if df is positive, dλ is negative...

What am I doing wrong??
 
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Where's the problem in that? One slope is positive and the other is negative - that's what you get when you have

λ= c/f and you write down dλ/df

No worries. Have faith in yourself and your maths.
 
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