How Do I Calculate Frequency with Planck's Equation?

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SUMMARY

The discussion centers on calculating the frequency of energy using Planck's equation, specifically for an energy value of 3.5 x 10^-14 joules. The relevant equation is E=hv, where E represents energy, h is Planck's constant (6.63 x 10^-34 joule-seconds), and v is the frequency. To find the frequency, the formula is rearranged to v = E/h. This straightforward application of Planck's equation allows for the calculation of frequency in hertz (Hz).

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  • Understanding of Planck's equation (E=hv)
  • Knowledge of Planck's constant (6.63 x 10^-34 joule-seconds)
  • Basic algebra for rearranging equations
  • Familiarity with units of energy (joules) and frequency (hertz)
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middleearth77
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Join Date: Jun 2005
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Read my Journal nd hlp. calculating frequency

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I have a problem that states as follows:

Calculate the frequency (in Hz) of energy of 3.5 x 10^-14 joules. (c=3.00 x 10^8 m/s; h=6.63 x 10^-34 joule-seconds)

I need help in setting this problem up. I found the equation E=hv, where E= the increase of energy, h= Planck's constant, and v= the freqency of light which increases propportionally with an increase in energy.

I am going crazy and just don't get it...
 
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[tex]E = h\nu \Rightarrow \nu = \frac{E}{h}[/tex]

[tex]E = 3.5 \times 10^{-14} J, h = 6.63 \times 10^{-34} J\cdot s[/tex]

Problem?
 
Welcome to Physics Forums, middleearth77!

This sounds like a homework problem, so I'm moving it to the appropriate section.
 

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