What is the frequency for a period of 60 microseconds?

  • Thread starter Thread starter taho2720
  • Start date Start date
  • Tags Tags
    Frequency
AI Thread Summary
To find the frequency for a period of 60 microseconds, the formula used is frequency = 1/period. Converting 60 microseconds to seconds gives 60 * 10^-6 seconds, leading to the calculation of frequency as 1/0.00006 seconds. This results in a frequency of 16,666.67 Hz, confirming the initial calculation was nearly correct. It's important to remember unit conversions when performing these calculations. Engaging in forums for clarification is encouraged to enhance understanding in electrical engineering concepts.
taho2720
Messages
1
Reaction score
0
hi all - I am a first year electrical engineer attending college at devry university. i haven't had any previous experience in electronics or engineering so I am really having a hard time grasping some of these concepts. anyway my teacher assigned some homework where the preiod and time are given, and all i need to do is find the frequency.

the first question has the first period at 60 us.

i knwo that frequency is equal to 1 over the period. so it would be 1/60us. i just can't seem to get a frequency that makes any sense out of this. i keep getting 16666.7 hz. is this anywhere near correct ?

i take the period in the denominator and multiply it by 10 to the -6 power because the unit is microseconds right ?

im sure you guys will be hearing a lot from me on these forums, as i have no previous experience in this field, so please don't flame me and call me names.
 
Last edited:
Physics news on Phys.org
Your method and answer are correct.
 



Hi there, don't worry about not having previous experience in this field. It can definitely be overwhelming at first, but with practice and patience, you'll get the hang of it.

To answer your question, you are on the right track. The frequency for a period of 60 microseconds can be calculated using the formula: frequency = 1/period. So in this case, it would be 1/60 microseconds. However, you are correct in converting the units to seconds before plugging it into the formula.

So the correct calculation would be: frequency = 1/(60 * 10^-6 seconds) = 1/0.00006 seconds = 16,666.67 Hz. So you were very close with your calculation, just remember to convert the units correctly.

Don't worry about asking questions on forums, that's what they are here for. It's always better to ask and learn, rather than staying confused and not understanding the concepts. Keep practicing and don't give up, you'll get the hang of it soon enough. Good luck!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top