yz = ln(x+z)
So I'm trying to find the tangent plane to the surface at a particular point (x0,y0,z0).
Here's the general formula:
Fx(x0,y0,z0)(x-x0) + Fy(x0,y0,z0)(y-y0) + Fz(x0,y0,z0)(z-z0) = 0,
where Fx, Fy, and Fz are the partial derivatives of the below F(x,y,z):
1. F(x,y,z) = ln(x+z)...