f(x,y,z,u,v)=xe^y+uz-\cos v=2
g(x,y,z,u,v)=u\cos y+x^2v-yz^2=1
I need to find u_z. When I try to do it by implicitly differentiating and solving the equation, I get 2 contradictory answers. If I try the formula, i.e.
f_z + f_uu_z + f_vv_z = 0
g_z + g_uu_z + g_vv_z = 0
I get an answer...