- #1
gillgill
- 128
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Find y'' by implicit differentiation
x^4+y^4=1
i found that y'=-x^3/y^3
y''=[(y^3)(-3x^2)-(-x^3)(3y^2)(y')]/(y^3)^2
y''=[-3x^2(y^3)-(-x^3)(3y^2)(-x^3/y^3)]/y^6
then i am stuck...please help...thanks
x^4+y^4=1
i found that y'=-x^3/y^3
y''=[(y^3)(-3x^2)-(-x^3)(3y^2)(y')]/(y^3)^2
y''=[-3x^2(y^3)-(-x^3)(3y^2)(-x^3/y^3)]/y^6
then i am stuck...please help...thanks