Griffiths Pg 133 4th Edition
Why can't n be negative? Is there a reason for this? My thought is that if n is negative, as sine is odd, the negative gets absorbed into C, a constant. Is this correct?
Would it be equally correct to let n be a negative integer?
Thank you
I want to explain my thoughts longer, but since my English is terrible, I will try to keep it as short as possible.
This is the Minkowski diagram for the question above. ct-axis is the worldline of the space station, and ct'-axis is the worldline of the spacecraft.
What I am confused about is...
I use an online physics calculator a lot to help me for various reasons. When I input less than 1 second into a watt hour calculation it initially tells me it can not be a negative value although that does disappear and it does do the calculation.
Example power 10 w time 0.01 seconds 0.1 J...
A diffuser normally decreases the velocity by increasing the area. With assumption of an incrompressible flow, according to Bernoulli, the static pressure increases. What happens if one "forces" the flow through a diffuser by applying a bigger pressure on the inlet than on the outlet?
the question is fairly easy to solve, integrating ##NiAB sin(\theta)## from ##\pi## to 0 or just do ##-NiAB(cos(0) - cos(\pi))## which gives you -2NiAB, but my textbook did not include the negative sign, is it mistaken?
What I mean is on a coordinate plane like below we take the positive x axis measure a certain distance x on it and take the infinitesmally small quantity dx next to it in the positive direction:
Now can I do the opposite as in can I measure a distance negative x on the negative x axis and...
My attempt:
4>19-3x
Subtract 19 from both sides:
-15 > -3x
Divide both sides by -3:
5 > x
Switch sides (change sign):
x < 5
! But Maths Genie tells me the answer is x>5
Where have I gone wrong?
Say I have 6 pencils. I want to times this by negative two. Now ignoring the rules that your teacher taught you work this out. 6 pencils negative 2 times. Negative one time would be 0 and another negative times would be -6 right? So 6 x - 2 = -6 according to simple logic. The calculator will say...
Suppose the following integration,
##\int_3^{-1} x^2 \, dx = \frac{1}{3}(-1)^3 - \frac{1}{3}(3)^3 = -\frac{28}{3}##
However, if we have a look at the graph,
The area between ##x = 3## and ##x = -1## is above the x-axis so should be positive. Dose anybody please know why the I am getting...
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So I have this question.
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here is the figure
and here is my correct solution
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A screenshot from a book which describes it:
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## F_{elevator} = w_{pass.} + w_{elev.} ##
## F = (70)(20 (num. of pass.))(9.8) + (800)(9.8) ##
## F_{elev.} = 21560N...
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This is the circuit in question.
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