0-60mph back down to 0 = X feet

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The discussion focuses on calculating the total distance traveled when accelerating from 0 to 60 mph and then decelerating back to 0. Given a 0-60 mph time of 6.7 seconds and a 60-0 mph braking distance of 112 feet, the acceleration is less effective than braking. Assuming uniform acceleration, the distance covered during the acceleration phase is approximately 295 feet, derived from the area of a triangle on a speed-time graph. This calculation indicates that the total distance for the entire 0-60-0 scenario is around 407 feet. Accurate estimations are crucial for the upcoming court appearance regarding the traffic citation.
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0-60-0 Help :(

I am going to court tomorrow for a trafic citation and need to figure out the following

0-60mph back down to 0 = X feet


information i have:

0-60 = 6.7 sec

60-0 = 112 feet
 
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It seems your braking (or was it a collision?) was much more effective than the acceleration. It is only possible to give an approximation answer in this case since your speed most likely did not change uniformly as you accelerated. If one assumes that it did change at a constant rate then the total distance traveled while going from 0 - 60 (0 - 88 ft/sec) is just the area under the speed time graph which will then be the area of a triangle with a base of 6.7 sec and a height of 88 feet/sec which gives a distance of 295 feet.
 

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