10 cm diameter loop in magnetic field

AI Thread Summary
The discussion focuses on calculating the induced emf and current in a 10 cm diameter loop placed in varying magnetic fields, with a resistance of 0.10 Ω. Using Faraday's Law, the induced emf for the first scenario is calculated as -3.93 × 10^-3 V, with the induced current expected to flow clockwise due to the opposing magnetic field. In the second scenario, as the magnetic flux decreases, the induced current is determined to flow counter-clockwise to oppose the change. The third scenario indicates no penetration of the magnetic field, resulting in zero emf and current. Participants are reminded to verify their application of the right-hand rule and to calculate the current values for each case.
ikihi
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Homework Statement



The figure shows a 10-cm diameter loop in three different magnetic fields. The loop's resistance is 0.10 Ω. For each case, determine the induced emf, the induced current, and the direction of the current.

p33-10.gif


Homework Equations



Faraday's Law: εinduced= - (ΔΦb/Δt) = - A ⋅ ΔB / Δt
Lenz's Law

The Attempt at a Solution



a)
εinduced= - (ΔΦb/Δt)
εinduced= -0.50 T/sec ⋅ π ⋅ 0.052m2
εinduced= -3.93 × 10-3 V

For part A: The flux is increasing, and the external magnetic field is going upward through the loop, so shouldn't the induced magnetic field go in opposite direction (downward) to oppose the external magnetic field? And so therefore shouldn't the induced current be clockwise around the loop according to the right hand rule?

b)
the flux is decreasing and the magnetic field is going into the loop (into the page). So since the flux through the loop is decreasing wouldn't this say that the the induced magnetic field goes in same direction of external magnetic field to try and prevent the decrease; and thus the current goes counter-clockwise?

c) The field does not penetrate the loop so the emf and current are 0.
 
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Your reasoning and answers are good, except check your right hand rule for b again.
 
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Don't forget to calculate the value of current in each case.
 
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