To achieve 1000 kNm of torque at 30 RPM, a motor's power output must be calculated, typically in kVA, which is essential for determining the motor's specifications. A 150 kVA, 3-phase motor running at 960 RPM can be paired with a double-stage gear system to reduce RPM effectively, with the first stage reducing by a ratio of 10:1 and the second by 3:1. The output torque can be calculated based on the motor's power and the gearing system, ensuring that the motor can handle the required load. The need for a flywheel depends on the load's variability, and engineers may consider alternatives like hydraulic motors for weight efficiency. Proper gear design, such as using an internal gear or epicyclic system, can also optimize performance while minimizing gearbox mass.