1st year physic help - hot air balloons

AI Thread Summary
The discussion focuses on calculating the average temperature of the air inside a hot air balloon using principles of buoyancy and gas laws. The buoyancy force is determined to be equal to the weight of the balloon and its passengers, leading to a calculation of the required density of the cooler air outside. The volume of the balloon is calculated, and the density of the cooler air is found to be 0.066 kg/m³. The participant questions whether it is valid to assume that the pressure inside the balloon matches the outside pressure of 90 kPa and discusses the relationship between temperatures and densities of the air inside and outside the balloon. The analysis is on track for determining the air temperature in the balloon.
bruceflea
Messages
11
Reaction score
0
1st year physics help - hot air balloons...

see next post...
 
Last edited:
Physics news on Phys.org
question:

The buoyancy force that pushes the balloon upward is proportional to the density of the cooler air outsider the balloon and the volume of the balloon, and can be expressed as

force buoyancy = denisty(ofcoolair)*g*volume(ofballoon)

where g is the gravitational constant.

Consider a 20-m-diameter hot-air balloon that, together with its cage, has a mass of 80 kg when empty. This balloon is hanging still in the air at a location where the atmospheric pressure and temperature are 90 kPa and 15 o C, respectively, while carrying three 65 kg people. Determine the average temperature of the air in the balloon.

this is what I have so far...

The buoyancy force required for the balloon to hang still in the air is equal to the force exerted downwards by the weight of the balloon so:

Force buoyancy, Fb = mass*gravity = 275*9.81 = 2697.75 N
Therefore:

denisty(ofcoolair)*g*volume(ofballoon) = 2697.75 N

volume(of balloon) = 4/3*pi*10^3 = 4188.79 m^3

density(ofcoolair) = 0.066 kg m^3

I know that for the balloon to be hanging still:

density(ofcoolair) = density(ofhotair)

Is it ok to assume that the pressure inside the balloon is the same as the outside (90kPa)? I'm also assuming that V1 = V2. Which would give me the expression:

T2/T1 = n1/n2

Am I heading in the right direction?
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top