2-D Poisson Equation Boundary Value Prob

Chingon
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Homework Statement


Solve the equation:
2F/∂x2 + ∂2F/∂y2 = f(x,y)

Boundary Conditions:
F=Fo for x=0
F=0 for x=a
∂F/∂y=0 for y=0 and y=b


Homework Equations


How can I find Eigengunctions of F(x,y) for expansion along Y in terms of X?


The Attempt at a Solution


I can't imagine what the Fourier transform of the generic f(x,y) looks like. Once this is done I'm supposed to be left with an ODE which is solvable.
 
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Ok, so based on my boundary conditions, I think I have to expand f(x,y) as a double Fourier cosine expansion, so:

f(x,y)= 1/2Ʃ(C2cos(n∏x/a) + C3cos(n∏y/b)) + ƩƩC4cos(m∏x/a)cos(n∏y/b)

Also, I can let F(x,y)=u(x,y)=X(x)Y(y)

Plugging that into the original Poisson equation I end up with:
1/X(x)∂2X/∂x2 + 1/Y(y)∂2Y/∂y2 = f(x,y)/X(x)Y(y)

I think I'm doing something wrong by having the right-hand side of the Poisson equation equal to f(x,y)/F(x,y). It's also not clear to me if I can solve for any of the Fourier expansion coefficients or reduce the equation...
 
Ok, so since ∂F/∂y = 0, that means it has a homogeneous solution of the form
Y=Ʃcos(n∏y/(b/2)) correct?

So that would cancel out the Y terms in the Fourier Expansion of f(x,y)?
 
Chingon said:

Homework Statement


Solve the equation:
2F/∂x2 + ∂2F/∂y2 = f(x,y)

Boundary Conditions:
F=Fo for x=0
F=0 for x=a
∂F/∂y=0 for y=0 and y=b

As with inhomogeneous linear ODEs, Poisson's equation can be solved by taking a particular solution F_p with
<br /> \nabla^2 F_p = f(x,y)<br />
subject to F_p = 0 on the boundary, and adding a complimentary function F_c where
<br /> \nabla^2 F_c = 0<br />
subject to the given boundary conditions for F.

To find F_p, you will want to find a family of eigenfunctions \phi_{nm}(x,y) such that
<br /> \nabla^2 \phi_{nm} = k_{nm}\phi_{nm}<br />
and such that \phi_{nm} vanishes on the boundary. You can then take a linear combination of these so that
<br /> F_p(x,y) = \sum_{n}\sum_m A_{nm} \phi_{nm}(x,y)<br />
with the A_{nm} chosen so that \nabla^2 F_p = f(x,y).
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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