2 Different answers given the same point and slope

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The discussion revolves around finding the equation of the tangent line at the point (1, 9) with a slope of 4. Two different equations were derived using two methods: the point-slope form and the slope-intercept form. The first method resulted in y = 4x - 3, while the second method gave y = 4x + 5, leading to confusion about the correct approach. The mistake was identified as a sign error in the calculations, emphasizing the common pitfalls of sign and copying errors in mathematical work. This highlights the importance of careful computation and verification in problem-solving.
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Homework Statement


Given the point (1,9) on a curve, and the slope = 4, what is the equation of the tangent line to the point?


Homework Equations


#1) y-y1 = m (x-x1)
or
#2) y = mx+b



The Attempt at a Solution


Using equation #1, I got y = 4x-3
Using equation #2, I got y = 4x+5

What am I doing wrong here?
 
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How did you get each of the answers in section 3 of your post?
 
Here are my computations:

1) y-y1 = m(x-x1):
y-1 = 4 (x-1)
y = 4x - 4 + 1
y = 4x -32) y = mx +b
9 = 4 (1) + b
5 = b
therefore, y = 4x + 5
 
fk378 said:
Here are my computations:

1) y-y1 = m(x-x1):
y-1 = 4 (x-1)
y = 4x - 4 + 1
y = 4x -3

In this point-slope equation, isn't y1 = 9?
 
Yes, you're right! I really made a silly mistake. Thank you!
 
fk378 said:
Yes, you're right! I really made a silly mistake. Thank you!

From my long years of having taken exams, graded exams, and helped students with post-mortems on exams, I can tell you that the number 1 type of mistake people make is *sign* errors and the number 2 type is *copying* errors. Everyone, including the professionals, makes them (occasionally, these errors even get into published journal papers!). Knowing this won't keep you from ever making mistakes again, but it does help you keep alert for where things may have gone wrong...
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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