2 masses, pulley on a frictionless incline

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In this discussion, a problem involving two masses connected by a cord over a frictionless pulley is analyzed. Mass m2, weighing 1.7 kg, is on a 30.5° incline, while mass m1, weighing 6.4 kg, is on a horizontal surface. A force of 13.3 N is applied to pull mass m2 up the incline. The user seeks clarification on how to calculate the tension in the cord, as the textbook does not provide adequate guidance on the topic. The force of 13.3 N is confirmed to be acting parallel to the incline, affecting the tension calculation.
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A 1.7 kg mass, m2, on a 30.5° incline is connected to a 6.4 kg mass, m1, on a horizontal surface. The surfaces and the pulley are frictionless. If F = 13.3 N, what is the magnitude of the tension in the connecting cord?
I've tried solving this by examining all the forces on both of the masses, but I can't seem to get it right (the homework is online through LON-CAPA). We haven't done anything relating to tension in class, and the book is somewhat unclear. A step in the right direction would be greatly appreciated.

EDIT: It appears that the image isn't working, so to make it clear, mass 2 is sitting on an incline (not off the edge) of 30.5 degrees and the pulley is in bottom of the incline while mass 1 is on a horizontal surface.
 
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I wish I could help, but the value of "F" listed above as 13.3 N seems a bit vague, what exactly is that referring to?
 
Wow, sorry I forgot to mention that. Wish the picture worked.

The force of 13.3 N is pulling mass 2 up the incline parallel to the incline itself.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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